Difficult
$0.25 \ g$ of an organic compound $A$ containing carbon, hydrogen, and oxygen was analysed using the combustion method. The increase in mass of the $CaCl_2$ tube and the potash bulb at the end of the experiment was found to be $0.15 \ g$ and $0.1837 \ g$, respectively. The percentage of oxygen in compound $A$ is $.... \%$. (Nearest integer)
(Given: molar mass in $g \ mol^{-1}$, $H: 1, C: 12, O: 16$)
(Given: molar mass in $g \ mol^{-1}$, $H: 1, C: 12, O: 16$)
- A$73$
- B$71$
- C$76$
- D$68$
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Similar Questions
In the Dumas method,$1 \ g$ of an organic compound gives $50 \ mL$ of $N_2$ gas at $300 \ K$ and $740 \ mm \ Hg$ pressure. If the aqueous tension at $300 \ K$ is $15 \ mm \ Hg$,what is the percentage of nitrogen in the compound?
In Dumas' method for estimation of nitrogen,$0.3 \ g$ of an organic compound gave $50 \ mL$ of nitrogen collected at $300 \ K$ temperature and $715 \ mm$ pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at $300 \ K = 15 \ mm$)
Medium
View SolutionIn Duma's method of estimation of nitrogen,$0.1840 \, g$ of an organic compound gave $30 \, mL$ of nitrogen collected at $287 \, K$ and $758 \, mm$ of $Hg$ pressure. The percentage composition of nitrogen in the compound is $......$ . (Round off to the Nearest Integer). [Given : Aqueous tension at $287 \, K = 14 \, mm$ of $Hg$ ]
DifficultJEE MAIN 2021
View SolutionExplain Quantitative Analysis.
Medium
View SolutionIn Dumas method,$0.3 \ g$ of an organic compound gave $45 \ mL$ of nitrogen at $STP$. The percentage of nitrogen is
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