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(A) The standard equation of a transverse wave is given by $y = A \sin(\omega t + kx + \phi)$.Comparing this with the given equation $y = 3 \sin(36t +

Vedclass · Accepted Answer

$349$

Vedclass · Answer

(A) The standard equation of a transverse wave is given by $y = A \sin(\omega t + kx + \phi)$.Comparing this with the given equation $y = 3 \sin(36t + 0.018x + \pi/4)$, we identify the wave number $k = 0.018 \ cm^{-1}$.The distance between two successive crests is equal to the wavelength $\lambda$.The relationship between wavelength and wave number is $\lambda = 2\pi / k$.Substituting the values: $\lambda = 2 	imes 3.14 / 0.018 = 6.28 / 0.018$.Calculating the value: $\lambda \approx 348.88 \ cm$.Rounding to the nearest integer, we get $\lambda = 349 \ cm$.

$A$ transverse wave on a string is described by $y = 3 \sin(36t + 0.018x + \pi/4)$, where $x$ and $y$ are in $cm$ and $t$ is in seconds. The least distance between two successive crests in the wave is . . . . . . $cm$. (Nearest integer) $(\pi = 3.14)$

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