$A$ particle executes a simple harmonic motion with a periodic time $8 \text{ s}$. At time $t = 0$, it is at a mean position. The ratio of the distance traveled by a particle in the $2^{nd}$ second and that in the $1^{st}$ second of its motion is $(\sin 45^\circ = \cos 45^\circ = \frac{1}{\sqrt{2}}, \sin 90^\circ = \cos 0^\circ = 1)$.

  • A
    $\frac{1}{\sqrt{2}}$
  • B
    $\sqrt{2}$
  • C
    $\sqrt{2} - 1$
  • D
    $\frac{1}{\sqrt{2} - 1}$

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