$A$ tuning fork of frequency $n$ produces $x$ beats per second when sounded with a vibrating sonometer string. What must have been the frequency of the string, when a slight increase in tension produces lesser beats per second than before?

Two tuning forks of frequencies $256$ and $258$ vibrations/sec are sounded together,then the time interval between consecutive maxima heard by the observer is ..... $sec$.

Two identical wires are vibrating in unison. If the tension in one of the wires is increased by $2 \%$,five beats are produced per second by the two vibrating wires. The initial frequency of each wire is $(\sqrt{1.02} \approx 1.01)$. (in $Hz$)

$41$ tuning forks are arranged in increasing order of frequency such that each produces $5 \text{ beats/second}$ with the next tuning fork. If the frequency of the last tuning fork is double that of the frequency of the first fork,then the frequency of the first and last fork is:

$A$ tuning fork of frequency $400 \ Hz$ is in unison with a sonometer wire. The number of beats heard per second,when the tension in the wire is increased by $1 \%$,will be

Two sound waves of wavelengths $5 \ m$ and $6 \ m$ produce $30$ beats in $3 \ s$. The velocity of sound is .... $m/s$.