$f(x) = \left| \begin{array}{ccc} x^3 & x^2 & 3x^2 \\ 1 & -6 & 4 \\ p & p^2 & p^3 \end{array} \right|$,where $p$ is a constant,then $\frac{d^3f(x)}{dx^3}$ is

  • A
    Proportional to $x^2$
  • B
    Proportional to $x$
  • C
    Proportional to $x^3$
  • D
    $A$ constant

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