$\int \frac{e^{\tan^{-1} x}}{1 + x^2} dx = $
- A$\log(1 + x^2) + c$
- B$\log e^{\tan^{-1} x} + c$
- C$e^{\tan^{-1} x} + c$
- D$\tan^{-1} e^{\tan^{-1} x} + c$
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