What is the hybridization of carbon in graphite and diamond,respectively?
- A$sp, sp^2$
- B$sp^2, sp^3$
- C$sp^3, sp^2$
- D$sp^3, sp^3$
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Similar Questions
Match the following ions with the corresponding hybridisation of their central atoms.
$A. NO_3^-$ $1. sp^3$ $B. NH_2^-$ $2. sp$ $C. SCN^-$ $3. sp^3d$ $D. ICl_2^-$ $4. sp^2$
| $A. NO_3^-$ | $1. sp^3$ |
| $B. NH_2^-$ | $2. sp$ |
| $C. SCN^-$ | $3. sp^3d$ |
| $D. ICl_2^-$ | $4. sp^2$ |
What is the decreasing order of carbon-carbon single bond length in the following compounds?
$(I) CH_2 = CH - C \equiv CH$
$(II) CH \equiv C - C \equiv CH$
$(III) CH_3 - CH = CH_2$
$(IV) CH_2 = CH - CH = CH_2$
$(I) CH_2 = CH - C \equiv CH$
$(II) CH \equiv C - C \equiv CH$
$(III) CH_3 - CH = CH_2$
$(IV) CH_2 = CH - CH = CH_2$
Difficult
View SolutionWhich bonds are formed by a carbon atom with $sp^{2}$-hybridisation?
Medium
View SolutionThe hybridisation state of chlorine in $ClF_3$ is
Medium
View SolutionIn $sp$ hybridisation,the shape is:
Medium
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