The hybridisation state of chlorine in $ClF_3$ is
- A$sp^3$
- B$sp^3d$
- C$sp^3d^2$
- D$sp^3d^3$
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Similar Questions
Identify the correct set from the following table:
Molecule Hybridisation of central atom Shape $(a)$ $PCl_5$ $dsp^3$ square pyramidal $(b)$ $[Ni(CN)_4]^{2-}$ $sp^3$ tetrahedral $(c)$ $SF_6$ $sp^3d^2$ octahedral $(d)$ $IF_3$ $dsp^3$ pyramidal
| Molecule | Hybridisation of central atom | Shape |
|---|---|---|
| $(a)$ $PCl_5$ | $dsp^3$ | square pyramidal |
| $(b)$ $[Ni(CN)_4]^{2-}$ | $sp^3$ | tetrahedral |
| $(c)$ $SF_6$ | $sp^3d^2$ | octahedral |
| $(d)$ $IF_3$ | $dsp^3$ | pyramidal |
Describe the hybridization in $PCl_{5}$. Why are the axial bonds longer as compared to equatorial bonds?
Difficult
View SolutionWhich of the following statements is incorrect?
Medium
View SolutionIn which of the following species is the hybrid state of the central atom the same?
Difficult
View SolutionThe increasing order of electronegativity of hybrid orbitals is ..........
Medium
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