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(A) $1$. The woman has a color-blind son $(X^cY)$ from her first marriage,which means she must be a carrier $(X^CX^c)$ for color blindness.$2$. In her

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$50\%$ sons color-blind + $50\%$ daughters color-blind

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(A) $1$. The woman has a color-blind son $(X^cY)$ from her first marriage,which means she must be a carrier $(X^CX^c)$ for color blindness.$2$. In her second marriage,she marries a color-blind man $(X^cY)$.$3$. The cross is: $X^CX^c 	imes X^cY$.$4$. The possible genotypes of the offspring are: $X^CX^c$ (normal vision daughter,carrier),$X^cX^c$ (color-blind daughter),$X^CY$ (normal vision son),and $X^cY$ (color-blind son).$5$. Thus,$50\%$ of the sons will be color-blind,and $50\%$ of the daughters will be color-blind (the other $50\%$ of daughters will be carriers).

$A$ woman with normal vision marries a man with normal vision and gives birth to a color-blind son. Her husband dies,and she remarries a color-blind man. What is the probability of color blindness in her children from the second marriage?

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