In the cross AABb times aaBb,the ratio of pro | vedclass

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(B) To find the ratio of the progeny for the cross $AABb 	imes aaBb$,we can analyze the inheritance of each gene pair independently (Mendel's Law of

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$1:2:1:0$

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(B) To find the ratio of the progeny for the cross $AABb 	imes aaBb$,we can analyze the inheritance of each gene pair independently (Mendel's Law of Independent Assortment).$1$. For the first gene pair $(AA 	imes aa)$: All offspring will be $Aa$. Thus,the ratio is $1$ $Aa$.$2$. For the second gene pair $(Bb 	imes Bb)$: This is a monohybrid cross resulting in a genotypic ratio of $1 BB : 2 Bb : 1 bb$.$3$. Combining these results:- $AaBB = 1 	imes 1 = 1$- $AaBb = 1 	imes 2 = 2$- $Aabb = 1 	imes 1 = 1$- $aabb = 1 	imes 0 = 0$Therefore,the ratio of $AaBB : AaBb : Aabb : aabb$ is $1:2:1:0$.

In the cross $AABb \times aaBb$,the ratio of progeny $AaBB : AaBb : Aabb : aabb$ is:

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