In a dihybrid cross,when F_1 plants (RrYy) ar | vedclass

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(B) In a dihybrid cross,the inheritance of two traits is considered independently. According to Mendel's Law of Independent Assortment,the alleles for

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$3$:$1$

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(B) In a dihybrid cross,the inheritance of two traits is considered independently. According to Mendel's Law of Independent Assortment,the alleles for seed color (Yellow $Y$ and Green $y$) segregate independently of the alleles for seed shape (Round $R$ and Wrinkled $r$).For the seed color trait,the $F_1$ generation is heterozygous $(Yy)$. When $F_1$ plants are self-hybridized $(Yy 	imes Yy)$,the resulting $F_2$ generation follows a monohybrid phenotypic ratio.The Punnett square for seed color yields: $1 YY$ (Yellow) : $2 Yy$ (Yellow) : $1 yy$ (Green).Thus,the total number of Yellow seeds is $3$ $(1 YY + 2 Yy)$ and the total number of Green seeds is $1$ $(1 yy)$.Therefore,the phenotypic segregation ratio of Yellow to Green seeds in the $F_2$ generation is $3:1$.

In a dihybrid cross,when $F_1$ plants $(RrYy)$ are self-hybridized,what is the segregation ratio of yellow and green seeds in the $F_2$ generation?

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