$A$ current of $10^{-3} \ A$ is flowing through a resistance of $1000 \ \Omega$. To measure the correct potential difference across this resistance,a voltmeter must be used whose resistance should be:

$A$ galvanometer coil has a resistance of $990 \,\Omega$. It shows a full-scale deflection for a current of $10 \,mA$. Calculate the value of the shunt resistance required to convert it into an ammeter of range $1 \,A$.

The resistance of a galvanometer coil is $R$. What is the shunt resistance required to convert it into an ammeter of range $4$ times?

In an experiment to find the resistance of a galvanometer by the half-deflection method, a $5 V$ battery and a high resistance of $4.9 k\Omega$ are connected in the circuit. In the absence of any shunt resistance, the galvanometer reads $20$ divisions when current flows in the circuit. To reduce the deflection by half, the value of the shunt resistance used is $98 \Omega$. The figure of merit of the galvanometer is given as $..... \mu A / \text{division}$.

$A$ moving coil galvanometer of resistance $100 \,\Omega$ is used as an ammeter using a shunt resistance of $0.1 \,\Omega$. The maximum deflection current in the galvanometer is $100 \,\mu A$. Find the minimum current in the circuit so that the ammeter shows maximum deflection in $mA$.

To convert a galvanometer into an ammeter,a shunt of $0.01\,\Omega$ is used. The resistance of the galvanometer coil is $50\,\Omega$ and its maximum deflection current is $20\,mA$. The range of the ammeter is: