What is the length of one full turn of the DN | vedclass

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(A) The $DNA$ double helix structure,as proposed by Watson and Crick,consists of a repeating unit called a pitch or a full turn.Each full turn of the

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$34\ \mathring{A}$

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(A) The $DNA$ double helix structure,as proposed by Watson and Crick,consists of a repeating unit called a pitch or a full turn.Each full turn of the $DNA$ helix consists of $10$ base pairs.The distance between two adjacent base pairs is $3.4\ \mathring{A}$ $(0.34\ nm)$.Therefore,the length of one full turn is $10 	imes 3.4\ \mathring{A} = 34\ \mathring{A}$ (or $3.4\ nm$).

What is the length of one full turn of the $DNA$ helix?

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