Select the correct complementary base pairing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Chargaff's rules and the structure of $DNA$ proposed by Watson and Crick,nitrogenous bases pair specifically through hydrogen bonds.I

Vedclass · Accepted Answer

Adenine and Thymine

Vedclass · Answer

(B) According to Chargaff's rules and the structure of $DNA$ proposed by Watson and Crick,nitrogenous bases pair specifically through hydrogen bonds.In $DNA$,Adenine $(A)$ always pairs with Thymine $(T)$ via two hydrogen bonds $(A=T)$.Guanine $(G)$ always pairs with Cytosine $(C)$ via three hydrogen bonds $(G≡C)$.Therefore,the correct complementary base pairing is Adenine and Thymine.

Column-$I$	Column-$II$
$P$. Bacteriophage $\phi \times 174$	$I$. $5386$ nucleotides
$Q$. Bacteriophage lambda	$II$. $48502 \, bp$
$R$. Escherichia coli	$III$. $3.3 \times 10^9 \, bp$
$S$. Human haploid $DNA$	$IV$. $4.6 \times 10^6 \, bp$

Select the correct complementary base pairing in $DNA$.

Similar Questions

State the characteristic feature of $DNA$ in organisms.

Mobile genetic elements $(transposons)$ replicate via an $.....$ intermediate.

In $DNA$,the unequal nitrogenous bases will primarily be ...

In the structure of $DNA$,if a purine base is present on one nucleotide strand,which nitrogenous base pairs with it?

Match the following columns:

Column-$I$ Column-$II$

$P$. Bacteriophage $\phi \times 174$ $I$. $5386$ nucleotides

$Q$. Bacteriophage lambda $II$. $48502 \, bp$

$R$. Escherichia coli $III$. $3.3 \times 10^9 \, bp$

$S$. Human haploid $DNA$ $IV$. $4.6 \times 10^6 \, bp$

Vedclass Test Series

Exam Paper Generator

Online Exam Module