What will be the enthalpy of formation of ben | vedclass

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(C) The required reaction is: $6C_{(s)} + 3H_{2(g)} \rightarrow C_6H_{6(l)}$ Given thermochemical equations: $(1) \ C_6H_{6(l)} + \frac{15}{2}O_{2(g)}

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$49.6$

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(C) The required reaction is: $6C_{(s)} + 3H_{2(g)} ightarrow C_6H_{6(l)}$ Given thermochemical equations: $(1) \ C_6H_{6(l)} + \frac{15}{2}O_{2(g)} ightarrow 6CO_{2(g)} + 3H_2O_{(l)} \quad \Delta H = -3268 \ kJ$ $(2) \ C_{(s)} + O_{2(g)} ightarrow CO_{2(g)} \quad \Delta H = -393.5 \ kJ$ $(3) \ H_{2(g)} + \frac{1}{2}O_{2(g)} ightarrow H_2O_{(l)} \quad \Delta H = -285.8 \ kJ$ To obtain the required reaction, we use Hess's Law: $\Delta H_f(C_6H_6) = [6 	imes \Delta H_f(CO_2) + 3 	imes \Delta H_f(H_2O)] - \Delta H_{comb}(C_6H_6)$ $\Delta H_f(C_6H_6) = [6 	imes (-393.5) + 3 	imes (-285.8)] - (-3268)$ $\Delta H_f(C_6H_6) = [-2361 - 857.4] + 3268$ $\Delta H_f(C_6H_6) = -3218.4 + 3268 = 49.6 \ kJ$

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