For a reaction at $25^o C$,$\Delta H > 0$ and $\Delta S > 0$. Under what conditions will this reaction become spontaneous?

  • A
    By increasing $T$
  • B
    By decreasing $T$
  • C
    By keeping $T$ constant
  • D
    By performing it in an open vessel at this temperature

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Similar Questions

For a given chemical reaction $A \rightarrow B$ at $300 \ K$,the free energy change is $-49.4 \ kJ \ mol^{-1}$ and the enthalpy of reaction is $51.4 \ kJ \ mol^{-1}$. The entropy change of the reaction is $..... \ J \ K^{-1} \ mol^{-1}$.

For a certain reaction, $\Delta H^0 = -345 \text{ kJ}$ and $\Delta S^0 = -123 \text{ JK}^{-1}$. At what temperature will the change over from spontaneous to non-spontaneous occur (in $\text{ K}$)?

Values of $\Delta H$ and $\Delta S$ for five different reactions are given below. On the basis of these values,predict which one of these will be spontaneous at all temperatures.
Reaction $\Delta H \ (kJ \ mol^{-1}) / \Delta S \ (J \ K^{-1} \ mol^{-1})$
$I$ $+98.0, +14.8$
$II$ $-55.5, -84.6$
$III$ $+28.3, -17.0$
$IV$ $-40.5, +24.6$
$V$ $+34.7, 0.0$

In all spontaneous processes,which of the following is true?

The correct thermodynamic conditions for a spontaneous reaction at all temperatures are:

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