For a given chemical reaction $A \rightarrow B$ at $300 \ K$,the free energy change is $-49.4 \ kJ \ mol^{-1}$ and the enthalpy of reaction is $51.4 \ kJ \ mol^{-1}$. The entropy change of the reaction is $..... \ J \ K^{-1} \ mol^{-1}$.
- A$336$
- B$390$
- C$460$
- D$551$
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For a reaction,$\Delta H = +3 \, kJ$ and $\Delta S = +10 \, J/K$. At what minimum temperature (in $K$) will the reaction become spontaneous?
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View SolutionCalculate the work done if $1 \ mole$ of an ideal gas is compressed isothermally and reversibly from $12 \ dm^3$ to $6 \ dm^3$ at $300 \ K$. $\left[R = 8.314 \ J \ K^{-1} \ mol^{-1}\right]$ (in $kJ$)
If the enthalpy and entropy change for a reaction at $298 \ K$ are $-145 \ kJ \ mol^{-1}$ and $-650 \ J \ K^{-1} \ mol^{-1}$ respectively,which one of the following statements is correct?
Values of $\Delta H$ and $\Delta S$ for five different reactions are given below. On the basis of these values,predict which one of these will be spontaneous at all temperatures.
Reaction $\Delta H \ (kJ \ mol^{-1}) / \Delta S \ (J \ K^{-1} \ mol^{-1})$ $I$ $+98.0, +14.8$ $II$ $-55.5, -84.6$ $III$ $+28.3, -17.0$ $IV$ $-40.5, +24.6$ $V$ $+34.7, 0.0$
| Reaction | $\Delta H \ (kJ \ mol^{-1}) / \Delta S \ (J \ K^{-1} \ mol^{-1})$ |
|---|---|
| $I$ | $+98.0, +14.8$ |
| $II$ | $-55.5, -84.6$ |
| $III$ | $+28.3, -17.0$ |
| $IV$ | $-40.5, +24.6$ |
| $V$ | $+34.7, 0.0$ |
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View SolutionWhat is the relationship between Gibbs free energy change,enthalpy change,and entropy change?
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