A 5 , L cylinder contains 10 , mol of O_2 gas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Initial volume $V_{initial} = 5 \, L$. Temperature $T = 27 + 273 = 300 \, K$. Final volume $V_{final}$ is the volume occupied by $10 \, mol$ of ga

Vedclass · Accepted Answer

$-1 	imes 241.3 \, L \cdot atm$

Vedclass · Answer

(C) Initial volume $V_{initial} = 5 \, L$. Temperature $T = 27 + 273 = 300 \, K$. Final volume $V_{final}$ is the volume occupied by $10 \, mol$ of gas at $1 \, atm$ pressure: $V_{final} = \frac{nRT}{P} = \frac{10 	imes 0.0821 	imes 300}{1} = 246.3 \, L$. Change in volume $\Delta V = V_{final} - V_{initial} = 246.3 - 5 = 241.3 \, L$. Work done $W = -P_{ext} \Delta V = -1 \, atm 	imes 241.3 \, L = -241.3 \, L \cdot atm$.

$A$ $5 \, L$ cylinder contains $10 \, mol$ of $O_2$ gas at $27 \, ^\circ C$. Due to a leak,the gas escapes into the atmosphere until the pressure inside the cylinder equals the atmospheric pressure $(1.0 \, atm)$. What is the work done by the gas?

Similar Questions

How will you calculate the work done on an ideal gas during compression,when the change in pressure is carried out in infinite steps?

What is meant by standard state in the context of the equation $\Delta U = q + w$?

Under isothermal condition,a gas at $300 \; K$ expands from $0.1 \; L$ to $0.25 \; L$ against a constant external pressure of $2 \; bar$. The work done by the gas is .... [Given that $1 \; L \; bar = 100 \; J$]

The enthalpies of the elements in their standard states are assumed to be

Identify the process having $\Delta V = 0$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module