A person adds 1.71 g of sugar (C_{12}H_{22}O | vedclass

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Question

(A) Moles of sugar $= \frac{1.71 \ g}{342 \ g/mol} = 0.005 \ mol = 5 	imes 10^{-3} \ mol$. Number of sugar molecules $= 5 	imes 10^{-3} 	imes 6.022

Vedclass · Accepted Answer

$3.6 	imes 10^{22}$

Vedclass · Answer

(A) Moles of sugar $= \frac{1.71 \ g}{342 \ g/mol} = 0.005 \ mol = 5 	imes 10^{-3} \ mol$. Number of sugar molecules $= 5 	imes 10^{-3} 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{21}$. Each molecule of sugar $(C_{12}H_{22}O_{11})$ contains $12$ carbon atoms. Total number of carbon atoms $= 12 	imes 3.011 	imes 10^{21} = 3.6132 	imes 10^{22} \approx 3.6 	imes 10^{22}$.

$A$ person adds $1.71 \ g$ of sugar $(C_{12}H_{22}O_{11})$ to sweeten their tea. How many carbon atoms are added? (Molar mass of sugar $= 342 \ g/mol$)

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