The empirical formula of a carbohydrate is CH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given that $0.1 \, 	ext{mol}$ of carbohydrate contains $1 \, g$ of hydrogen,then $1 \, 	ext{mol}$ of carbohydrate contains $10 \, g$ of hydrogen

Vedclass · Accepted Answer

$C_5H_{10}O_5$

Vedclass · Answer

(A) Given that $0.1 \, 	ext{mol}$ of carbohydrate contains $1 \, g$ of hydrogen,then $1 \, 	ext{mol}$ of carbohydrate contains $10 \, g$ of hydrogen.The empirical formula is $CH_2O$,so the molecular formula can be represented as $(CH_2O)_n$ or $C_nH_{2n}O_n$.The number of hydrogen atoms in $1 \, 	ext{mol}$ of the compound is $2n \, 	ext{mol}$.Since the molar mass of hydrogen is $1 \, 	ext{g/mol}$,the mass of hydrogen is $2n 	imes 1 \, 	ext{g} = 10 \, 	ext{g}$.Solving for $n$: $2n = 10$,which gives $n = 5$.Therefore,the molecular formula is $C_5H_{10}O_5$.

The empirical formula of a carbohydrate is $CH_2O$. If $0.1 \, \text{mol}$ of this carbohydrate contains $1 \, g$ of hydrogen,what is its molecular formula?

Similar Questions

An organic compound contains carbon,hydrogen,and oxygen with percentages of $38.71\%$,$9.67\%$,and $51.62\%$ respectively. Determine the empirical formula of this compound.

The molecular mass of caffeine is $194 \, a.m.u.$. It contains $28.9 \%$ of nitrogen by mass. The number of nitrogen atoms in one molecule of caffeine is ...............

In $CH_3CH_2Br$,the percentage of $Br$ is:

On reduction with hydrogen,$3.6 \ g$ of an oxide of metal $(M)$ left $3.2 \ g$ of the metal. If the atomic weight of the metal is $64$,the formula of the oxide is:

What is the percentage of nitrogen in urea (in $\%$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module