(A) Given: Number of molecules $= 6.022 \times 10^{20}$.Volume of solution $= 100 \ mL = 0.1 \ L$.Number of moles of urea $= \frac{\text{Number of mol

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(A) Given: Number of molecules $= 6.022 \times 10^{20}$.Volume of solution $= 100 \ mL = 0.1 \ L$.Number of moles of urea $= \frac{\text{Number of molecules}}{N_A} = \frac{6.022 \times 10^{20}}{6.022 \times 10^{23}} = 10^{-3} \ mol$.Molarity $(M) = \frac{\text{moles of solute}}{\text{volume of solution in liters}}$.$M = \frac{10^{-3} \ mol}{0.1 \ L} = 0.01 \ M$.

Class 11 Chemistry Some Basic Concepts of Chemistry The mole concept

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If $100 \ mL$ of a urea solution contains $6.022 \times 10^{20}$ molecules,what is the concentration of the urea solution in $M$?

A
$0.01$
B
$0.001$
C
$0.2$
D
$0.1$

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Some Basic Concepts of Chemistry

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The mole concept

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If $100 \ mL$ of a urea solution contains $6.022 \times 10^{20}$ molecules,what is the concentration of the urea solution in $M$?

Similar Questions

Calculate the number of atoms in the following: $(i)$ $52 \ mol$ of $Ar$ $(ii)$ $52 \ u$ of $He$ $(iii)$ $52 \ g$ of $He$

The number of moles of sodium oxide in $620 \ g$ of it is ................ $moles$.

$A$ person adds $1.71 \ g$ of sugar $(C_{12}H_{22}O_{11})$ to sweeten their tea. How many carbon atoms are added? (Molar mass of sugar $= 342 \ g/mol$)

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