If 1 , mL of water contains 20 drops,then the | vedclass

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(D) Density of water is $1 \, g/mL$. Therefore,$1 \, mL$ of water has a mass of $1 \, g$. Molar mass of water $(H_2O)$ is $18 \, g/mol$. Number of mol

Vedclass · Accepted Answer

$1.673 	imes 10^{21}$ molecules

Vedclass · Answer

(D) Density of water is $1 \, g/mL$. Therefore,$1 \, mL$ of water has a mass of $1 \, g$. Molar mass of water $(H_2O)$ is $18 \, g/mol$. Number of moles in $1 \, mL$ of water = $\frac{1 \, g}{18 \, g/mol} = 0.0556 \, mol$. Number of molecules in $1 \, mL$ of water = $0.0556 	imes 6.022 	imes 10^{23} \approx 3.346 	imes 10^{22}$ molecules. Since $1 \, mL$ contains $20$ drops,the number of molecules in $1$ drop = $\frac{3.346 	imes 10^{22}}{20} = 1.673 	imes 10^{21}$ molecules.

If $1 \, mL$ of water contains $20$ drops,then the number of molecules in $1$ drop of water is:

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