If a metal oxide contains $32\%$ oxygen,what is the equivalent mass of the metal?

One atomic mass unit $(amu)$ is equal to:

Chlorine has two naturally occurring isotopes,${}^{35}Cl$ and ${}^{37}Cl$. If the atomic mass of $Cl$ is $35.45$,the ratio of natural abundance of ${}^{35}Cl$ and ${}^{37}Cl$ is closest to (in $: 1$)

On reduction with hydrogen,$3.6 \, g$ of an oxide of a metal left $3.2 \, g$ of metal. If the equivalent weight of the metal is $32$,the simplest formula of the oxide would be:

$10 \text{ g}$ of a metal $(M)$ reacts with oxygen to form $11.6 \text{ g}$ of oxide. What is the equivalent weight of $M$?

The modern basis of atomic weight is