On reduction with hydrogen,$3.6 \, g$ of an oxide of a metal left $3.2 \, g$ of metal. If the equivalent weight of the metal is $32$,the simplest formula of the oxide would be:

  • A
    $MO$
  • B
    $M_2O_3$
  • C
    $MO_2$
  • D
    $M_2O$

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