What are the equivalent weights of H_3PO_4 in | vedclass

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(A) The equivalent weight of an acid is given by the formula: $	ext{Equivalent weight} = \frac{	ext{Molar mass}}{	ext{n-factor}}$.The molar mass of

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$98, 49, 32.67$

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(A) The equivalent weight of an acid is given by the formula: $	ext{Equivalent weight} = \frac{	ext{Molar mass}}{	ext{n-factor}}$.The molar mass of $H_3PO_4$ is $98 \ g/mol$.In the first reaction,$H_3PO_4 + OH^{-} ightarrow H_2PO_4^{-} + H_2O$,the $n$-factor is $1$ (one $H^+$ is replaced).Equivalent weight $= 98 / 1 = 98$.In the second reaction,$H_3PO_4 + 2OH^{-} ightarrow HPO_4^{2-} + 2H_2O$,the $n$-factor is $2$ (two $H^+$ are replaced).Equivalent weight $= 98 / 2 = 49$.In the third reaction,$H_3PO_4 + 3OH^{-} ightarrow PO_4^{3-} + 3H_2O$,the $n$-factor is $3$ (three $H^+$ are replaced).Equivalent weight $= 98 / 3 = 32.67$.Thus,the equivalent weights are $98, 49, 32.67$.

What are the equivalent weights of $H_3PO_4$ in the following reactions respectively?
$H_3PO_4 + OH^{-} \rightarrow H_2PO_4^{-} + H_2O$
$H_3PO_4 + 2OH^{-} \rightarrow HPO_4^{2-} + 2H_2O$
$H_3PO_4 + 3OH^{-} \rightarrow PO_4^{3-} + 3H_2O$

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What are the equivalent weights of $H_3PO_4$ in the following reactions respectively?$H_3PO_4 + OH^{-} \rightarrow H_2PO_4^{-} + H_2O$$H_3PO_4 + 2OH^{-} \rightarrow HPO_4^{2-} + 2H_2O$$H_3PO_4 + 3OH^{-} \rightarrow PO_4^{3-} + 3H_2O$