(A) For $XY_2$: $0.1 \ mol$ of $XY_2 = 10 \ g$ $1 \ mol$ of $XY_2 = 100 \ g$ So,$X + 2Y = 100$ (Equation $1$) For $X_3Y_2$: $0.05 \ mol$ of $X_3Y_2 =

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(A) For $XY_2$: $0.1 \ mol$ of $XY_2 = 10 \ g$ $1 \ mol$ of $XY_2 = 100 \ g$ So,$X + 2Y = 100$ (Equation $1$) For $X_3Y_2$: $0.05 \ mol$ of $X_3Y_2 = 9 \ g$ $1 \ mol$ of $X_3Y_2 = 180 \ g$ So,$3X + 2Y = 180$ (Equation $2$) Subtracting Equation $1$ from Equation $2$: $(3X + 2Y) - (X + 2Y) = 180 - 100$ $2X = 80 \implies X = 40$ Substituting $X = 40$ in Equation $1$: $40 + 2Y = 100$ $2Y = 60 \implies Y = 30$ Therefore,the atomic weights of $X$ and $Y$ are $40$ and $30$ respectively.

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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Suppose the elements $X$ and $Y$ combine to form two compounds $XY_2$ and $X_3Y_2.$ When $0.1 \ mol$ of $XY_2$ weighs $10 \ g$ and $0.05 \ mol$ of $X_3Y_2$ weighs $9 \ g,$ the atomic weights of $X$ and $Y$ are

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A
$40, 30$
B
$60, 40$
C
$20, 30$
D
$30, 20$

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Some Basic Concepts of Chemistry

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Atomic, Molecular and Equivalent masses

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Suppose the elements $X$ and $Y$ combine to form two compounds $XY_2$ and $X_3Y_2.$ When $0.1 \ mol$ of $XY_2$ weighs $10 \ g$ and $0.05 \ mol$ of $X_3Y_2$ weighs $9 \ g,$ the atomic weights of $X$ and $Y$ are

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The specific heat of a metal is $0.031 \ cal \ g^{-1} \ ^\circ C^{-1}$ and its equivalent weight is $103.6$. What is the exact atomic weight of the metal?

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