The number of moles of electrons in 1 kg of | vedclass

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Question

(D) The mass of one electron is $m_e = 9.108 	imes 10^{-31} \ kg$.The number of electrons in $1 \ kg$ is $N = \frac{1 \ kg}{9.108 	imes 10^{-31} \ k

Vedclass · Accepted Answer

$\frac{1}{9.108 	imes 6.022} 	imes 10^8$

Vedclass · Answer

(D) The mass of one electron is $m_e = 9.108 	imes 10^{-31} \ kg$.The number of electrons in $1 \ kg$ is $N = \frac{1 \ kg}{9.108 	imes 10^{-31} \ kg} = \frac{1}{9.108} 	imes 10^{31}$.The number of moles of electrons is given by $n = \frac{N}{N_A}$,where $N_A = 6.022 	imes 10^{23} \ mol^{-1}$.Therefore,$n = \frac{1}{9.108 	imes 10^{-31}} 	imes \frac{1}{6.022 	imes 10^{23}} = \frac{1}{9.108 	imes 6.022} 	imes 10^{31-23} = \frac{1}{9.108 	imes 6.022} 	imes 10^8$.

The number of moles of electrons in $1 \ kg$ of electrons is .......

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