(D) Density of water is $1 \, g/mL$. Therefore,$1 \, L$ of water $= 1000 \, mL = 1000 \, g$. Number of moles of water $= \frac{\text{mass}}{\text{mola

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$55.55 \times 6.022 \times 10^{23}$

(D) Density of water is $1 \, g/mL$. Therefore,$1 \, L$ of water $= 1000 \, mL = 1000 \, g$. Number of moles of water $= \frac{\text{mass}}{\text{molar mass}} = \frac{1000 \, g}{18 \, g/mol} = 55.55 \, mol$. Number of molecules $= \text{moles} \times N_A = 55.55 \times 6.022 \times 10^{23}$ molecules.