Which of the following contains the maximum n | vedclass

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(A) To find the number of atoms,we use the formula: $	ext{Number of atoms} = 	ext{Number of moles} 	imes N_A$. $A) \, 24 \, g \, C = \frac{24}{12}

Vedclass · Accepted Answer

$24 \, g \, C \, (12)$

Vedclass · Answer

(A) To find the number of atoms,we use the formula: $	ext{Number of atoms} = 	ext{Number of moles} 	imes N_A$. $A) \, 24 \, g \, C = \frac{24}{12} = 2 \, 	ext{moles} = 2 	imes N_A \, 	ext{atoms}$. $B) \, 56 \, g \, Fe = \frac{56}{56} = 1 \, 	ext{mole} = 1 	imes N_A \, 	ext{atoms}$. $C) \, 27 \, g \, Al = \frac{27}{27} = 1 \, 	ext{mole} = 1 	imes N_A \, 	ext{atoms}$. $D) \, 108 \, g \, Ag = \frac{108}{108} = 1 \, 	ext{mole} = 1 	imes N_A \, 	ext{atoms}$. Comparing the results,$24 \, g \, C$ contains the maximum number of atoms $(2 	imes N_A)$.

Which of the following contains the maximum number of atoms?

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