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(D) The number of oxygen atoms is calculated as: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{number of oxy

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$2 \ g$ of water

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(D) The number of oxygen atoms is calculated as: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{number of oxygen atoms in one molecule}$.For $2 \ g$ of $CO$ $(M = 28 \ g/mol)$: $\frac{2}{28} 	imes 1 = 0.071 \ N_A$.For $2 \ g$ of $CO_2$ $(M = 44 \ g/mol)$: $\frac{2}{44} 	imes 2 = 0.091 \ N_A$.For $2 \ g$ of $SO_2$ $(M = 64 \ g/mol)$: $\frac{2}{64} 	imes 2 = 0.0625 \ N_A$.For $2 \ g$ of $H_2O$ $(M = 18 \ g/mol)$: $\frac{2}{18} 	imes 1 = 0.111 \ N_A$.Comparing the values,$2 \ g$ of $H_2O$ contains the maximum number of oxygen atoms.

Which one of the following has the maximum number of atoms of oxygen?

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