$5.06 \ g$ of pure cupric oxide $(CuO)$ on complete reduction gives $4.04 \ g$ of metallic copper. In another experiment,$1.3 \ g$ of metallic copper is dissolved in nitric acid and the resulting solution is carefully dried to yield $1.63 \ g$ of $CuO$. Which law of chemical combination is illustrated by these results?

  • A
    Law of Equivalent Proportions
  • B
    Law of Definite Proportions
  • C
    Law of Multiple Proportions
  • D
    Law of Conservation of Mass

Explore More

Similar Questions

$A$ chemical equation is balanced according to the law of

Define the Law of Multiple Proportions.

$2 \ g$ of hydrogen combine with $16 \ g$ of oxygen to form water and with $6 \ g$ of carbon to form methane. In carbon dioxide,$12 \ g$ of carbon are combined with $32 \ g$ of oxygen. These figures illustrate the law of:

Difficult
View Solution

Two elements $x$ and $y$ have atomic masses $14$ and $16$ respectively. They form a series of five compounds $A, B, C, D, E$ in which the ratio of $x$ to $y$ is $1:2:3:4:5$. If compound $A$ contains $28$ parts by weight of $x$ and $16$ parts by weight of $y$,then in compound $C$,how many parts by weight of $x$ will combine with $24$ parts by weight of $y$?

The law of multiple proportions was proposed by

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo