Two bulbs B_1 and B_2 contain 10 g each of O | vedclass

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(C) For bulb $B_1$ ($10 \ g$ of $O_2$):Molar mass of $O_2 = 32 \ g/mol$.Number of molecules $= (10 / 32) 	imes N_A = 0.3125 \ N_A$.Number of atoms $=

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$B_1$ has more molecules but equal number of atoms.

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(C) For bulb $B_1$ ($10 \ g$ of $O_2$):Molar mass of $O_2 = 32 \ g/mol$.Number of molecules $= (10 / 32) 	imes N_A = 0.3125 \ N_A$.Number of atoms $= 2 	imes (10 / 32) 	imes N_A = 0.625 \ N_A$.For bulb $B_2$ ($10 \ g$ of $O_3$):Molar mass of $O_3 = 48 \ g/mol$.Number of molecules $= (10 / 48) 	imes N_A = 0.2083 \ N_A$.Number of atoms $= 3 	imes (10 / 48) 	imes N_A = 0.625 \ N_A$.Comparing the results:Number of molecules: $0.3125 \ N_A (B_1) > 0.2083 \ N_A (B_2)$.Number of atoms: $0.625 \ N_A (B_1) = 0.625 \ N_A (B_2)$.Therefore,bulb $B_1$ contains more molecules,and both bulbs contain an equal number of atoms.

Two bulbs $B_1$ and $B_2$ contain $10 \ g$ each of $O_2$ and $O_3$ respectively. Which bulb contains a greater number of molecules and atoms?

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