The number of water molecules present in a dr | vedclass

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(D) The molar mass of $H_{2}O$ is $18 \ g/mol$.$18 \ g$ of $H_{2}O$ contains $6.022 	imes 10^{23}$ molecules.Therefore,$0.018 \ g$ of $H_{2}O$ contai

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$6.022 	imes 10^{20}$

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(D) The molar mass of $H_{2}O$ is $18 \ g/mol$.$18 \ g$ of $H_{2}O$ contains $6.022 	imes 10^{23}$ molecules.Therefore,$0.018 \ g$ of $H_{2}O$ contains:$	ext{Number of molecules} = \frac{	ext{Given mass}}{	ext{Molar mass}} 	imes N_{A}$$= \frac{0.018 \ g}{18 \ g/mol} 	imes 6.022 	imes 10^{23} 	ext{ molecules/mol}$$= 0.001 	imes 6.022 	imes 10^{23}$$= 6.022 	imes 10^{20} 	ext{ molecules}$.

The number of water molecules present in a drop of water weighing $0.018 \ g$ is

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