$A$ $64 \, g$ organic compound contains $24 \, g$ of carbon,$8 \, g$ of hydrogen,and the rest is oxygen. The empirical formula of this compound is .....

An organic compound with $C = 40\%$ and $H = 6.7\%$ will have the empirical formula

An organic compound has a molar mass of $108 \ g \ mol^{-1}$. The atoms $C, H,$ and $N$ are present in the weight ratio of $9 : 1 : 3.5$. What is the molecular formula of the compound?

Calculate the percentage composition of the following elements:
$(a)$ Sulphur in $CN_4H_4S$
$(b)$ Carbon in $C_2H_4O_2$
$(c)$ Nitrogen in $CN_2H_2O$
$(d)$ Hydrogen in $C_6H_6$
Given atomic masses: $C = 12, H = 1, O = 16, N = 14, S = 32$.

The empirical formula of a compound is $CH_2O$ and its molecular mass is $90$. The molecular formula of the compound is:

An organic compound has an empirical formula $CH_2O$,its vapour density is $45$. The molecular formula of the compound is