Nitrate is detected by the ring test. The bro | vedclass

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Question

(B) The brown ring test for nitrate ions $(NO_3^-)$ involves adding freshly prepared ferrous sulfate $(FeSO_4)$ solution to the nitrate solution,follo

Vedclass · Accepted Answer

$[Fe(H_2O)_5(NO)]^{2+}$

Vedclass · Answer

(B) The brown ring test for nitrate ions $(NO_3^-)$ involves adding freshly prepared ferrous sulfate $(FeSO_4)$ solution to the nitrate solution,followed by the careful addition of concentrated sulfuric acid $(H_2SO_4)$ along the sides of the test tube. The reaction produces a brown-colored complex,nitrosoferrous sulfate,which is represented as $[Fe(H_2O)_5(NO)]SO_4$ or simply $[Fe(H_2O)_5(NO)]^{2+}$. This complex is responsible for the characteristic brown ring formed at the junction of the two layers.

Nitrate is detected by the ring test. The brown color of the ring is due to which of the following?

Similar Questions

$50 \, mL$ of $0.2 \, M$ solution of a compound with empirical formula $CoCl_3 \cdot 4NH_3$ on treatment with excess of $AgNO_{3(aq)}$ yields $1.435 \, g$ of $AgCl$. Ammonia is not removed by treatment with concentrated $H_2SO_4$. The formula of the compound is:

The correct order of molar conductivity of the following complex compounds in aqueous solution is:
$(I) K[Co(NH_3)_2(NO_2)_4]$
$(II) [Cr(NH_3)_3(NO_2)_3]$
$(III) [Cr(NH_3)_5NO_2]_3[Co(NO_2)_6]_2$
$(IV) Mg[Cr(NH_3)(NO_2)_5]$

Which among the following cations forms a least stable complex if the ligand is same?

$CuSO_4$ solution reacts with excess of $KCN$ solution to form:

The solubility of $AgCl$ in $NH_4OH$ is due to the formation of:

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