An ideal gas at 300 , K expands from a volume | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here,$P_{ext} = 1 	i

Vedclass · Accepted Answer

$-900 \, J$

Vedclass · Answer

(A) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here,$P_{ext} = 1 	imes 10^5 \, N \, m^{-2}$. Change in volume $\Delta V = V_f - V_i = (1 	imes 10^{-2} - 1 	imes 10^{-3}) \, m^3 = (10 	imes 10^{-3} - 1 	imes 10^{-3}) \, m^3 = 9 	imes 10^{-3} \, m^3$. Substituting the values: $W = -(1 	imes 10^5) 	imes (9 	imes 10^{-3}) = -900 \, J$. Since the gas expands,work is done by the system,hence the value is negative.

An ideal gas at $300 \, K$ expands from a volume of $1 \times 10^{-3} \, m^3$ to $1 \times 10^{-2} \, m^3$ against a constant external pressure of $1 \times 10^5 \, N \, m^{-2}$. Calculate the work done.

Similar Questions

Give the formula that shows the relationship between the boiling point and the enthalpy of evaporation of a solvent.

Which among the following is $NOT$ an intensive property?

Among the quantities,density $(\rho)$,temperature $(T)$,enthalpy $(H)$,heat capacity $(C_p)$,volume $(V)$ and pressure $(p)$,a set of intensive variables are

$A$ $5 \, L$ cylinder contains $10 \, mol$ of $O_2$ gas at $27 \, ^\circ C$. Due to a leak,the gas escapes into the atmosphere until the pressure inside the cylinder equals the atmospheric pressure $(1.0 \, atm)$. What is the work done by the gas?

$A$ system is changed from state $A$ to state $B$ by one path and from $B$ to $A$ by another path. If $E_1$ and $E_2$ are the corresponding changes in internal energy,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module