(C) Number of atoms of $A$ per unit cell $= 8 \times \frac{1}{8} = 1$.Number of atoms of $B$ per unit cell $= 6 \times \frac{1}{2} = 3$.The ratio of $

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(C) Number of atoms of $A$ per unit cell $= 8 \times \frac{1}{8} = 1$.Number of atoms of $B$ per unit cell $= 6 \times \frac{1}{2} = 3$.The ratio of $A:B = 1:3$.Therefore,the formula of the compound is $AB_3$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

Easy

$A$ compound is formed by elements $A$ and $B$. Element $A$ occupies the corners of the cube,and element $B$ occupies the face centers. What is the formula of the compound?

A
$A_4B_3$
B
$A_2B$
C
$AB_3$
D
$A_2B_3$

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Crystal structure and Coordination number

The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites is $A_{x}B$. The value of $x$ is ..... .
(Integer answer)

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If $a$ is the length of the side of a cube,the distance between the body-centered atom and one corner atom in the cube will be

MediumNEET 2014

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EasyMHT CET 2026

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The number of close neighbours in a body-centred cubic $(BCC)$ lattice of identical spheres is:

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$A$ metal $X$ crystallises in a face-centred cubic arrangement with the edge length $862 \, pm$. What is the shortest separation of any two nuclei of the atom? ........... $\, pm$

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$A$ compound is formed by elements $A$ and $B$. Element $A$ occupies the corners of the cube,and element $B$ occupies the face centers. What is the formula of the compound?

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The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites is $A_{x}B$. The value of $x$ is ..... .(Integer answer)

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The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites is $A_{x}B$. The value of $x$ is ..... .
(Integer answer)