The ratio of the rms speed of H_2 at 50 K to | vedclass

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(C) The formula for $rms$ speed is $u_{rms} = \sqrt{\frac{3RT}{M}}$.For $H_2$ at $T_1 = 50 \ K$ and $M_1 = 2 \ g/mol$,and $O_2$ at $T_2 = 800 \ K$ and

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$1$

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(C) The formula for $rms$ speed is $u_{rms} = \sqrt{\frac{3RT}{M}}$.For $H_2$ at $T_1 = 50 \ K$ and $M_1 = 2 \ g/mol$,and $O_2$ at $T_2 = 800 \ K$ and $M_2 = 32 \ g/mol$:$\frac{u_{H_2}}{u_{O_2}} = \sqrt{\frac{T_1}{M_1} 	imes \frac{M_2}{T_2}}$$\frac{u_{H_2}}{u_{O_2}} = \sqrt{\frac{50}{2} 	imes \frac{32}{800}}$$\frac{u_{H_2}}{u_{O_2}} = \sqrt{25 	imes \frac{1}{25}} = \sqrt{1} = 1$.

The ratio of the $rms$ speed of $H_2$ at $50 \ K$ to the $rms$ speed of $O_2$ at $800 \ K$ is ......

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