How many unit cells are present in a 1.00 g | vedclass

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(C) The molar mass of $NaCl$ is $58.5 \ g/mol$. An $fcc$ unit cell of $NaCl$ contains $4$ formula units of $NaCl$. The mass of one unit cell is calcul

Vedclass · Accepted Answer

$2.57 	imes 10^{21} \ 	ext{unit cells}$

Vedclass · Answer

(C) The molar mass of $NaCl$ is $58.5 \ g/mol$. An $fcc$ unit cell of $NaCl$ contains $4$ formula units of $NaCl$. The mass of one unit cell is calculated as: $	ext{Mass} = \frac{4 	imes 58.5}{6.022 	imes 10^{23}} \ g$. To find the number of unit cells in $1.00 \ g$,we divide the total mass by the mass of one unit cell: $	ext{Number of unit cells} = \frac{1.00 \ g}{(4 	imes 58.5) / (6.022 	imes 10^{23}) \ g} = \frac{6.022 	imes 10^{23}}{234} \approx 2.57 	imes 10^{21} \ 	ext{unit cells}$.

How many unit cells are present in a $1.00 \ g$ cube of ideal $NaCl$ crystal?

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