Which of the following statements is false ba | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The compressibility factor $Z$ is defined as $Z = \frac{PV}{nRT}$.For a van der Waals gas,the equation is $(P + \frac{an^2}{V^2})(V - nb) = nRT$.A

Vedclass · Accepted Answer

The dashed curve represents an ideal gas where $a = 0$ and $b = 0$.

Vedclass · Answer

(D) The compressibility factor $Z$ is defined as $Z = \frac{PV}{nRT}$.For a van der Waals gas,the equation is $(P + \frac{an^2}{V^2})(V - nb) = nRT$.At low pressure,$Z \approx 1 - \frac{a}{RTV}P$,which explains the initial decrease in $Z$ for real gases (where $a > 0$).At high pressure,$Z \approx 1 + \frac{Pb}{RT}$,which explains the increase in $Z$ for real gases (where $b > 0$).Gas $A$ shows $Z > 1$ for all $P$,implying $a = 0$ and $b > 0$.Gas $B$ shows $Z  0$ and $b = 0$.The dashed curve represents a typical real gas where both $a$ and $b$ are non-zero.Therefore,the statement that the dashed curve represents an ideal gas is false.

Which of the following statements is false based on the provided graph of compressibility factor $Z$ versus pressure $P$?

Similar Questions

$CH_4$ gas is behaving non-ideally. The compressibility factor for the gas is $1.5$ at $2 \ atm$ and $400 \ K$. Calculate the molar volume for the gas in $litre$. [Given $R = 0.08 \ L \ atm \ K^{-1} \ mol^{-1}$]

Assertion : Compressibility factor $(Z)$ for non-ideal gases can be greater than $1$.
Reason : Non-ideal gases always exert higher pressure than expected.

In the van der Waals equation for real gases,which of the following terms represents the correction for intermolecular forces?

Which of the following can be most easily liquefied? (Value of $a$ for $NH_3 = 4.17, CO_2 = 3.59, SO_2 = 6.71, Cl_2 = 6.49$)

$A$ $Van \ der \ Waals$ real gas acts as an ideal gas under which of the following conditions?

Vedclass Test Series

Exam Paper Generator

Online Exam Module