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(D) In a $CCP$ structure,there are $8$ corners and $6$ face centers.Number of $A$ atoms at corners initially $= 8 	imes \frac{1}{8} = 1$.Since $2$ at

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$AB_4$

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(D) In a $CCP$ structure,there are $8$ corners and $6$ face centers.Number of $A$ atoms at corners initially $= 8 	imes \frac{1}{8} = 1$.Since $2$ atoms of $A$ are missing from the corners,the effective number of $A$ atoms $= 1 - (2 	imes \frac{1}{8}) = 1 - \frac{1}{4} = \frac{3}{4}$.Number of $B$ atoms at face centers $= 6 	imes \frac{1}{2} = 3$.The ratio $A:B = \frac{3}{4} : 3 = 3:12 = 1:4$.Therefore,the molecular formula is $AB_4$.

$A$ compound is formed by elements $A$ and $B$ which crystallizes in a $CCP$ structure. Atoms of $A$ are at the corners and atoms of $B$ are at the face centers. If two atoms of $A$ are missing from the unit cell,what is the molecular formula of the compound?

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