For the quantization of the Bohr orbit,its ci | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the de Broglie hypothesis,a particle of mass $m$ moving with velocity $v$ has an associated wavelength $\lambda = \frac{h}{mv}$.For a

Vedclass · Accepted Answer

$= n\lambda$

Vedclass · Answer

(A) According to the de Broglie hypothesis,a particle of mass $m$ moving with velocity $v$ has an associated wavelength $\lambda = \frac{h}{mv}$.For an electron moving in a circular orbit of radius $r$,the circumference is $2\pi r$.Bohr's quantization condition states that the angular momentum is quantized as $mvr = \frac{nh}{2\pi}$,which rearranges to $2\pi r = \frac{nh}{mv}$.Substituting $\lambda = \frac{h}{mv}$ into the equation,we get $2\pi r = n\lambda$.Thus,the circumference of the orbit must be an integral multiple of the de Broglie wavelength for a stable orbit.

For the quantization of the Bohr orbit,its circumference will be equal to .......

Similar Questions

If the radius of the first orbit of the $H$ atom is $a_0$, then the de Broglie wavelength of the electron in the third orbit will be ....... (in $\pi a_0$)

What is the de Broglie wavelength of a tennis ball weighing $66 \ g$ moving with a velocity of $10 \ m/s$?

With what velocity must an electron travel,so that its momentum is equal to that of a photon of wavelength $663 \ nm$ (in $m/s$)?

The wavelength of the electron emitted by a metal sheet of work function $4 \ eV$ when photons from $EMR$ of wavelength $124 \ nm$ strike the metal plate is ........... $nm$.

The de Broglie equation describes the relationship between the wavelength associated with the motion of an electron and its:

Vedclass Test Series

Exam Paper Generator

Online Exam Module