The angular momentum of the 2^{nd} Bohr orbit | vedclass

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(D) The angular momentum of an electron in a Bohr orbit is given by the formula $L = \frac{nh}{2\pi}$.For the $2^{nd}$ Bohr orbit of the $H$ atom,$n =

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$x$

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(D) The angular momentum of an electron in a Bohr orbit is given by the formula $L = \frac{nh}{2\pi}$.For the $2^{nd}$ Bohr orbit of the $H$ atom,$n = 2$,so $x = \frac{2h}{2\pi} = \frac{h}{\pi}$.The $1^{st}$ excited state of $Li^{+2}$ corresponds to $n = 2$ (since the ground state is $n = 1$).Therefore,the angular momentum for $n = 2$ is $L = \frac{2h}{2\pi} = \frac{h}{\pi} = x$.Thus,the angular momentum remains $x$.

The angular momentum of the $2^{nd}$ Bohr orbit of the $H$ atom is $x$. Find the angular momentum of the $1^{st}$ excited state of $Li^{+2}$.

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