If the wavelength is 5894 , mathring{A},the v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the De Broglie relation,the momentum $p = \frac{h}{\lambda}$.Since $p = m 	imes c$,we have $m = \frac{h}{\lambda 	imes c}$.Given: $

Vedclass · Accepted Answer

$3.746 	imes 10^{-36}$

Vedclass · Answer

(D) According to the De Broglie relation,the momentum $p = \frac{h}{\lambda}$.Since $p = m 	imes c$,we have $m = \frac{h}{\lambda 	imes c}$.Given: $h = 6.6252 	imes 10^{-34} \, kg \cdot m^2/s$,$\lambda = 5894 \, \mathring{A} = 5894 	imes 10^{-10} \, m$,and $c = 3 	imes 10^8 \, m/s$.Substituting the values:$m = \frac{6.6252 	imes 10^{-34}}{5894 	imes 10^{-10} 	imes 3 	imes 10^8}$$m = \frac{6.6252 	imes 10^{-34}}{17682 	imes 10^{-2}}$$m = 0.00037468 	imes 10^{-32} \, kg$$m = 3.746 	imes 10^{-36} \, kg$.

If the wavelength is $5894 \, \mathring{A}$,the velocity of light is $3 \times 10^8 \, m/s$,and the value of $h$ is $6.6252 \times 10^{-34} \, kg \cdot m^2/s$,what will be the mass of a sodium photon?

Similar Questions

If the de Broglie wavelength of an electron is $728.14 \ nm$,its kinetic energy in $J$ is: (mass of electron $= 9.1 \times 10^{-31} \ kg$; $h = 6.626 \times 10^{-34} \ J \ s$)

What is the wavelength of an electron? What does it indicate?

The ratio of de Broglie wavelengths of two particles,having mass ratio $1 : 3$ and kinetic energy ratio $2 : 1$ is

If the kinetic energy of an electron is $2.8 \times 10^{-23} \ J$,then the de Broglie wavelength will be ....... $(m_e = 9.1 \times 10^{-31} \ kg)$.

$A$ ball weighing $25 \, g$ moves with a velocity of $6.6 \times 10^4 \, cm/sec$. The de Broglie wavelength associated with it is .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module