The solubility product constants (K_{sp}) for | vedclass

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(A) For $1:1$ electrolytes like $AgCl$,$AgBr$,and $AgI$,the solubility $S = \sqrt{K_{sp}}$.For $AgCl$: $S = \sqrt{2 	imes 10^{-10}} \approx 1.41 	im

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$Ag_2CO_3$

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(A) For $1:1$ electrolytes like $AgCl$,$AgBr$,and $AgI$,the solubility $S = \sqrt{K_{sp}}$.For $AgCl$: $S = \sqrt{2 	imes 10^{-10}} \approx 1.41 	imes 10^{-5} \ M$.For $AgBr$: $S = \sqrt{5 	imes 10^{-13}} \approx 7.07 	imes 10^{-7} \ M$.For $AgI$: $S = \sqrt{8 	imes 10^{-17}} \approx 8.94 	imes 10^{-9} \ M$.For $Ag_2CO_3$ ($1:2$ electrolyte),$K_{sp} = 4S^3$,so $S = (K_{sp}/4)^{1/3} = (8 	imes 10^{-12} / 4)^{1/3} = (2 	imes 10^{-12})^{1/3} \approx 1.26 	imes 10^{-4} \ M$.Comparing the values,$Ag_2CO_3$ has the highest solubility.

The solubility product constants $(K_{sp})$ for some silver salts are given as: $AgCl = 2 \times 10^{-10}$,$AgBr = 5 \times 10^{-13}$,$Ag_2CO_3 = 8 \times 10^{-12}$,and $AgI = 8 \times 10^{-17}$. Which of the following salts has the highest solubility?

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