(A) $NaOCl$ is a salt of a strong base and a weak acid.The formula for the degree of hydrolysis $(h)$ is $h = \sqrt{\frac{K_h}{C}}$.Given $K_h = 10^{-

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(A) $NaOCl$ is a salt of a strong base and a weak acid.The formula for the degree of hydrolysis $(h)$ is $h = \sqrt{\frac{K_h}{C}}$.Given $K_h = 10^{-6}$ and $C = 0.01 \ M = 10^{-2} \ M$.$h = \sqrt{\frac{10^{-6}}{10^{-2}}} = \sqrt{10^{-4}} = 10^{-2}$.Percentage of hydrolysis = $h \times 100 = 10^{-2} \times 100 = 1\%$.