1.825 g of HCl is dissolved in 5 L of water | vedclass

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(D) The molar mass of $HCl$ is $36.5 \ g/mol$. Number of moles of $HCl = \frac{1.825 \ g}{36.5 \ g/mol} = 0.05 \ mol$. Concentration of $H^+ = [H^+] =

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$10^{-2}, 10^{-12}$

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(D) The molar mass of $HCl$ is $36.5 \ g/mol$. Number of moles of $HCl = \frac{1.825 \ g}{36.5 \ g/mol} = 0.05 \ mol$. Concentration of $H^+ = [H^+] = \frac{	ext{moles of } HCl}{	ext{volume in } L} = \frac{0.05 \ mol}{5 \ L} = 0.01 \ M = 10^{-2} \ M$. Using the ionic product of water,$K_w = [H^+][OH^-] = 10^{-14}$. $[OH^-] = \frac{K_w}{[H^+]} = \frac{10^{-14}}{10^{-2}} = 10^{-12} \ M$.

$1.825 \ g$ of $HCl$ is dissolved in $5 \ L$ of water. What are the concentrations of $H^+$ and $OH^-$ ions?

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