At $298 \ K$,the solubility of $PbCl_2$ is $2 \times 10^{-2} \ mol/L$. Calculate the $K_{sp}$.
- A$1 \times 10^{-7}$
- B$3.2 \times 10^{-5}$
- C$1 \times 10^{-5}$
- D$3.2 \times 10^{-6}$
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