Calculate the hydrolysis constant $(K_h)$ for a salt containing $NO_2^-$. Given that the dissociation constant $(K_a)$ for $HNO_2$ is $4.5 \times 10^{-4}$ and the ionic product of water $(K_w)$ is $1.0 \times 10^{-14}$.

  • A
    $2.22 \times 10^{-11}$
  • B
    $2.02 \times 10^{-10}$
  • C
    $4.33 \times 10^{-12}$
  • D
    $3.03 \times 10^{-11}$

Explore More

Similar Questions

Which of the following salts when dissolved in water will get hydrolysed?

The $pH$ of a $0.02 \ M \ NH_4Cl$ solution will be [given $K_b \ (NH_4OH) = 10^{-5}$ and $\log \ 2 = 0.301$ ]

The degree of hydrolysis of a $N/100$ $KCN$ solution is = ....... (Given $K_a = 1.4 \times 10^{-9}$)

An aqueous solution of potassium formate is ...........

Assertion $: -$ The aqueous solution of $Na_3PO_4$ is basic in nature.
Reason $: -$ $Na_3PO_4$ in its aqueous solution undergoes anionic hydrolysis.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo