$A$ smooth sphere of radius $R$ moves along a straight line with a constant acceleration $a = g$. $A$ particle is placed at the top of the sphere. It is released from there with zero velocity relative to the sphere. What will be its speed relative to the sphere as a function of the angle $\theta$ as the particle slides?

  • A
    $\frac{\sqrt{Rg(\sin \theta + \cos \theta)}}{2}$
  • B
    $\sqrt{Rg(1 + \cos \theta - \sin \theta)}$
  • C
    $\sqrt{4Rg \sin \theta}$
  • D
    $\sqrt{2Rg(1 + \sin \theta - \cos \theta)}$

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